To resolve the question, we need to analyze the statements based on vector addition and resultant force. Given the forces \((\vec{p} + \vec{q})\) and \((\vec{p} - \vec{q})\), and knowing that these vectors are orthogonal (\(\vec{p} \perp \vec{q}\)), we will use the formula for the magnitude of the resultant of two forces:
\(R = \sqrt{A^2 + B^2 + 2AB\cos\theta}\)
where \(A = \|\vec{p} + \vec{q}\|\) and \(B = \|\vec{p} - \vec{q}\|\).
- For Statement I: When the resultant is \(\sqrt{3(p^2 + q^2)}\), we have:
- \(R_1 = \sqrt{3(p^2 + q^2)}\)
- \(R_1 = \sqrt{2(p^2 + q^2) + 2pq\cos\theta_1}\)
- \(3(p^2 + q^2) = 2(p^2 + q^2) + 2pq\cos\theta_1\)
- \(pq\cos\theta_1 = (p^2 + q^2)/2\)
- For Resultant \(\sqrt{2(p^2 + q^2)}\), using a similar process:
- \(R_2 = \sqrt{2(p^2 + q^2)}\)
- \(R_2 = \sqrt{2(p^2 + q^2) + 2pq\cos\theta_2}\)
- \(2(p^2 + q^2) = 2(p^2 + q^2) + 2pq\cos\theta_2\)
- \(pq\cos\theta_2 = 0\)
- This implies \(\theta_2 = 90^\circ\).
- Hence, based on the given conditions:
- From \(\theta_1\): \(<\theta_2\), and the geometry of vectors:
- For \(\theta_1\) solution, \(\theta_1 = 60^\circ\).
Thus, both statements are consistent:
- Statement I asserts the condition of angles during the resultant calculations are consistent.
- Statement II correctly assigns \(\theta_1 = 60^\circ\) and \(\theta_2 = 90^\circ\).
Conclusion: Both Statement I and Statement II are true. Therefore, the correct answer is:
Both Statement I and Statement II are true.