Question:medium

Statement I : Two forces \((\vec{p} + \vec{q})\) and \((\vec{p} - \vec{q})\) where \(\vec{p} \perp \vec{q}\), when act at an angle \(\theta_1\) to each other, the magnitude of their resultant is \(\sqrt{3(p^2 + q^2)}\), when they act at an angle \(\theta_2\), the magnitude of their resultant becomes \(\sqrt{2(p^2 + q^2)}\). This is possible only when \(\theta_1<\theta_2\).
Statement II : In the situation given above, \(\theta_1 = 60^{\circ}\) and \(\theta_2 = 90^{\circ}\).
In the light of the above statements, choose the most appropriate answer from the options given below :

Show Hint

If two vectors have equal magnitude \(A\), their resultant is \(2A \cos(\theta/2)\). In this problem, both vectors have magnitude \(\sqrt{p^2+q^2}\) because they are perpendicular diagonals of a rectangle formed by \(p\) and \(q\).
Updated On: Mar 19, 2026
  • Both Statement I and Statement II are true.
  • Both Statement I and Statement II are false.
  • Statement I is true but Statement II is false.
  • Statement I is false but Statement II is true.
Show Solution

The Correct Option is A

Solution and Explanation

To resolve the question, we need to analyze the statements based on vector addition and resultant force. Given the forces \((\vec{p} + \vec{q})\) and \((\vec{p} - \vec{q})\), and knowing that these vectors are orthogonal (\(\vec{p} \perp \vec{q}\)), we will use the formula for the magnitude of the resultant of two forces:

\(R = \sqrt{A^2 + B^2 + 2AB\cos\theta}\)

where \(A = \|\vec{p} + \vec{q}\|\) and \(B = \|\vec{p} - \vec{q}\|\).

  1. For Statement I: When the resultant is \(\sqrt{3(p^2 + q^2)}\), we have:
    • \(R_1 = \sqrt{3(p^2 + q^2)}\)
    • \(R_1 = \sqrt{2(p^2 + q^2) + 2pq\cos\theta_1}\)
    • \(3(p^2 + q^2) = 2(p^2 + q^2) + 2pq\cos\theta_1\)
    • \(pq\cos\theta_1 = (p^2 + q^2)/2\)
  2. For Resultant \(\sqrt{2(p^2 + q^2)}\), using a similar process:
    • \(R_2 = \sqrt{2(p^2 + q^2)}\)
    • \(R_2 = \sqrt{2(p^2 + q^2) + 2pq\cos\theta_2}\)
    • \(2(p^2 + q^2) = 2(p^2 + q^2) + 2pq\cos\theta_2\)
    • \(pq\cos\theta_2 = 0\)
    • This implies \(\theta_2 = 90^\circ\).
  3. Hence, based on the given conditions:
    • From \(\theta_1\): \(<\theta_2\), and the geometry of vectors:
      • For \(\theta_1\) solution, \(\theta_1 = 60^\circ\).

Thus, both statements are consistent:

  1. Statement I asserts the condition of angles during the resultant calculations are consistent.
  2. Statement II correctly assigns \(\theta_1 = 60^\circ\) and \(\theta_2 = 90^\circ\).

Conclusion: Both Statement I and Statement II are true. Therefore, the correct answer is:

Both Statement I and Statement II are true. 
 

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