Question:medium

Statement-I:
Major product is ortho substituted product and minor product is para substituted.
Statement-II:
Ortho \& Para substituted products can be separated by steam distillation.

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In Reimer-Tiemann reaction, ortho and para products can be separated by steam distillation due to their different boiling points.
Updated On: Jan 22, 2026
  • Statement-I and Statement-II both are correct.
  • Statement-I and Statement-II both are incorrect.
  • Only Statement-I is correct.
  • Only Statement-II is correct.
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Identify Element M.
M does not react with dilute HCl to release hydrogen. This places M below Hydrogen in the electrochemical series. A common example fitting the subsequent reactions (forming a complex with KCN) is Copper (Cu).
Step 2: Reaction with KCN.
Copper(II) sulfate reacts with excess KCN. First, it forms Cu(CN)$_2$, which decomposes to CuCN (Cu is reduced to +1 state) and releases cyanogen gas. Then, CuCN dissolves in excess KCN to form the stable complex $K_3[Cu(CN)_4]$. \[ \text{Complex P} = [Cu(CN)_4]^{3-} \]
Step 3: Reaction with H$_2$S.
The cyano-complex of Copper(I) is extremely stable. When H$_2$S is passed through it, the concentration of free copper ions is insufficient to exceed the solubility product of copper sulfide. Therefore, no precipitate of MS is formed. Conclusion: The amount of MS formed is 0.
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