This query requires assessing the validity of two assertions concerning aniline's chemical behavior and selecting the option that accurately reflects their correctness.
The evaluation hinges on the principles of Electrophilic Aromatic Substitution (EAS) and the impact of substituents on the benzene ring's reactivity.
Step 1: Analyze Statement (I).
"The NH₂ group in Aniline is ortho and para directing and a powerful activating group."
The amino group (–NH₂) in aniline features a nitrogen atom with a lone pair of electrons. This lone pair can engage in resonance with the benzene ring, delocalizing electron density within the ring. This phenomenon is termed the +R (or +M) effect.
Resonance structures demonstrate an increased electron density specifically at the ortho and para positions. Consequently, these positions are highly prone to electrophilic attack, establishing the –NH₂ group as an ortho and para director.
Moreover, the +R effect's donation of electron density to the entire ring renders it significantly more reactive towards electrophiles than benzene itself. The pronounced +R effect of the –NH₂ group classifies it as a powerful activating group.
Therefore, Statement (I) is accurate.
Step 2: Analyze Statement (II).
"Aniline does not undergo Friedel-Crafts reaction (alkylation and acylation)."
The Friedel-Crafts reaction requires a Lewis acid catalyst, typically anhydrous \(\text{AlCl}_3\). Aniline, with its nitrogen lone pair, functions as a Lewis base.
Upon mixing aniline with the \(\text{AlCl}_3\) catalyst, a strong acid-base reaction ensues before alkylation or acylation can occur. The basic nitrogen atom of aniline donates its lone pair to the Lewis acid \(\text{AlCl}_3\), forming a salt.
\[ \text{C}_6\text{H}_5\ddot{\text{N}}\text{H}_2 + \text{AlCl}_3 \longrightarrow \text{C}_6\text{H}_5\stackrel{+}{\text{N}}\text{H}_2\text{--}\stackrel{-}{\text{Al}}\text{Cl}_3 \]
This salt formation results in the nitrogen atom carrying a formal positive charge. The resultant anilinium-type group (\(–\text{N}^+\text{H}_2\text{--}\)) acts as a potent electron-withdrawing group (strong -I effect), severely deactivating the benzene ring towards electrophilic attack. The ring becomes so electron-deficient that it cannot react with the electrophile (carbocation or acylium ion) necessary for the Friedel-Crafts reaction.
Therefore, Statement (II) is also accurate.
Both Statement (I) and Statement (II) are factually correct. Statement (I) accurately describes the general activating and directing properties of the amino group, while Statement (II) highlights a specific instance where reactivity is inhibited due to interaction with the Lewis acid catalyst employed in Friedel-Crafts reactions.
Thus, Both Statement (I) and Statement (II) are true.

Identify the major product (G) in the following reaction (Bromination with \( Br_2/FeBr_3 \)). 
