Step 1: The tightest rule is "F not in P1," so fix P1's makeup first: its two seats must come from A, B, C, D, E only.
Step 2: B needs C or F alongside; since F cannot be in P1, any P1 slot containing B forces C into P1 as well, and every other choice for P1 pushes B's C/F partner into P2 or P3 instead.
Step 3: Layering the A–D separation and the E-not-with-C rule on top of each P1 choice, and keeping only the combinations that survive all four rules, the tally comes to
\[ \boxed{12} \]
Final Answer: 12.