To determine which of the given salts corresponds to $\text{X}$ (soluble in water), $\text{Y}$ (sparingly soluble in water), and $\text{Z}$ (soluble only in hot water), let's analyze the solubility properties of each compound listed in the options.
- Solubility in Water:
- $\text{X}$: Salt that is soluble in water. In the list of options, \(\text{AlCl}_3\) (aluminum chloride) is known to be highly soluble in water.
- $\text{Y}$: Salt that is sparingly soluble in water. Among the listed compounds, \(\text{AgCl}\) (silver chloride) is well-known for being sparingly soluble in water.
- $\text{Z}$: Salt that is soluble only in hot water. Lead chloride, \(\text{PbCl}_2\), is known for its unique solubility property; it is sparingly soluble in cold water but becomes more soluble in hot water.
- Analyzing the Options:
- Option 1: $\text{AgCl}$, $\text{Hg}_2\text{Cl}_2$, $\text{PbCl}_2$. - $\text{AgCl}$ is indeed sparingly soluble, but $\text{Hg}_2\text{Cl}_2$ is neither highly soluble in water nor only soluble in hot water.
- Option 2: $\text{AlCl}_3$, $\text{AgCl}$, $\text{PbCl}_2$. - Matches perfectly with the properties discussed: $\text{AlCl}_3$ is soluble in water, $\text{AgCl}$ is sparingly soluble, and $\text{PbCl}_2$ is soluble in hot water.
- Option 3: $\text{BaCl}_2$, $\text{PbCl}_2$, $\text{Hg}_2\text{Cl}_2$. - $\text{BaCl}_2$ is soluble, but $\text{Hg}_2\text{Cl}_2$ does not fit the hot water solubility requirement.
- Option 4: $\text{MgCl}_2$, $\text{Hg}_2\text{Cl}_2$, $\text{CaCl}_2$. - $\text{MgCl}_2$ is soluble in water, but again, $\text{Hg}_2\text{Cl}_2$ and $\text{CaCl}_2$ don't match the required descriptions.
- Conclusion: Based on the reasoning above, Option 2 is the correct choice, where $\text{AlCl}_3$ is soluble in water, $\text{AgCl}$ is sparingly soluble, and $\text{PbCl}_2$ is soluble only in hot water.