To determine the molarity, first calculate the moles of NaOH: \[ \text{Moles of NaOH} = \frac{\text{Mass}}{\text{Molar mass}} = \frac{8.0 \, \text{g}}{40 \, \text{g/mol}} = 0.2 \, \text{mol} \] Then, calculate the molarity of the solution: \[ \text{Molarity} = \frac{\text{Moles of solute}}{\text{Volume of solution in liters}} = \frac{0.2 \, \text{mol}}{2.0 \, \text{L}} = 0.10 \, \text{M} \] The solution's molarity is \( 0.10 \, \text{M} \).