Question

Phthalimide is made to undergo following sequence of reactions.

Total number of \( \pi \) bonds present in product 'P' is/are ______

Answer 1

Correct Answer: 8

Phthalimide is transformed as follows:
KOH deprotonates phthalimide, yielding the phthalimide anion.
The phthalimide anion undergoes an S\(_N2\) reaction with benzyl chloride to form product 'P'.
Product 'P' contains:
3 \(\pi\)-bonds from the benzene ring.
4 \(\pi\)-bonds from the two carbonyl groups (2 \(\pi\)-bonds per group).
1 \(\pi\)-bond from the benzyl group attached to nitrogen.
The total \(\pi\)-bonds in product 'P' are:
\[3 + 2 + 2 + 1 = 8\]