To find the number of non-negative integral solutions for the equation \( a + b + 2c = 22 \), we will use the concept of stars and bars in combination with managing constraints due to the coefficient of \( c \).
The equation given is:
a + b + 2c = 22
where \( a, b, \) and \( c \) are non-negative integers.
Let's redefine the equation by considering different values for \( c \) because it has a coefficient of 2.
Rewriting \( a + b = 22 - 2c \), we will find the possible values of \( c \) and for each, the solutions to the modified equation.
We perform these calculations:
Thus, sum these values:
23 + 21 + 19 + …….. + 1 = 144
This is an arithmetic series where the first term \( a = 23 \), the last term is 1, and the number of terms is 12 (since \( c \) ranges from 0 to 11).
The sum of an arithmetic series is given by:
\[\text{Sum} = \frac{n}{2} \times (\text{first term} + \text{last term})\]
Substituting the values, we get:
\[\text{Sum} = \frac{12}{2} \times (23 + 1) = 6 \times 24 = 144\]
Therefore, the number of non-negative integral solutions is 144.
If \[ \sum_{r=1}^{30} r^2 \left( \binom{30}{r} \right)^2 = \alpha \times 2^{29}, \] then \( \alpha \) is equal to _______.