Step 1: Apply the combinatorial sum identity.
The identity is:
\[
\sum_{r=1}^{n} r^2 \binom{n}{r}^2 = n(n+1) \binom{2n}{n}/4.
\]
For \( n = 30 \), this becomes:
\[
\sum_{r=1}^{30} r^2 \binom{30}{r}^2 = \frac{30 \times 31}{4} \binom{60}{30}.
\]
Step 2: Approximate and simplify.
Using \( \binom{60}{30} \approx 2^{59} / \sqrt{30} \), the expression simplifies to:
\[
\alpha = 930.
\]
Therefore, the final answer is \( \boxed{930} \).