Question

Match List I with List II

	List I -Type of Hydride		List II-Example
A	Electron deficient hydride	I	MgH2
B	Electron rich hydride	II	HF
C	Electron precise hydride	III	B2H6
D	Saline hydride	IV	CH4

Choose the correct answer from the options given below:

• A. A-II, B-III, C-I, D-IV
• B. A-II, B-III, C-IV, D-I
• C. A-III, B-II, C-I, D-IV
• D. A-III, B-II, C-I, D-IV

Answer 1

The Correct Option is C

Here, we need to match the types of hydrides in List I with their correct examples in List II. To solve this problem, let's first understand each type of hydride:

1. Electron deficient hydride: These hydrides have fewer electrons than needed for the formation of regular covalent bonds. An example of this type of hydride is B₂H₆ (Diborane), which exhibits electron deficiency in its bonding.
2. Electron rich hydride: These hydrides have more electrons than are necessary for bond formation and usually exhibit lone pairs of electrons. An example is HF (Hydrogen fluoride), which has a lone pair of electrons on the fluorine atom, making it electron-rich.
3. Electron precise hydride: These hydrides have just the right number of electrons required for normal covalent bond formation. A typical example is CH₄ (Methane), where carbon shares its electrons in a way that completes the tetrahedral configuration.
4. Saline hydride: These are ionic compounds formed by the reaction of hydrogen with highly electropositive metals and include a hydride ion (H^-). An example of a saline hydride is MgH₂ (Magnesium hydride).

From this explanation, we can now match each type with its correct example:

• Electron deficient hydride matches with III: B₂H₆
• Electron rich hydride matches with II: HF
• Electron precise hydride matches with IV: CH₄
• Saline hydride matches with I: MgH₂

Therefore, the correct matching of List I with List II is:

• A - III
• B - II
• C - IV
• D - I

Hence, the correct answer is: A-III, B-II, C-IV, D-I.