Question

Match List-I with List-II

	List I		List II
A.	Lyophilic colloid	i	Liquid-liquid colloid
B.	Emulsion	ii	Protective colloid
C.	Positively charged	iii	\(FeCl_3 + NaOH\)
D.	Negatively charged	iv	\(FeCl_3 + hot\; water\)

Choose the correct answer from the options given below :

• A. (A)-(II), (B)-(I), (C)-(IV), (D)-(III)
• B. (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
• C. (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
• D. (A)-(III), (B)-(II), (C)-(I), (D)-(IV)

Answer 1

The Correct Option is A

To solve this question, we need to correctly match the items from List-I with those in List-II. Let's analyze each pair one by one:

1. Lyophilic colloid: Lyophilic colloids are also known as protective colloids because they are stable and protect the dispersed phase from precipitation. So, Lyophilic colloid corresponds to Protective colloid. Hence, (A)-(II).
2. Emulsion: An emulsion is a type of colloid in which both dispersed phase and dispersion medium are liquids. Therefore, Emulsion corresponds to Liquid-liquid colloid. Hence, (B)-(I).
3. Positively charged: A positively charged colloid system can be formed when \( \text{FeCl}_3 \) is added to hot water, leading to the formation of positively charged \( \text{Fe(OH)}_3 \) sol. Therefore, Positively charged corresponds to \( \text{FeCl}_3 + \text{hot water} \). Hence, (C)-(IV).
4. Negatively charged: A negatively charged colloid system can be prepared when \( \text{FeCl}_3 \) reacts with \( \text{NaOH} \), forming negatively charged \( \text{Fe(OH)}_3 \) sol. Consequently, Negatively charged corresponds to \( \text{FeCl}_3 + \text{NaOH} \). Hence, (D)-(III).

By analyzing the pairs, the correct matches are:

• (A)-(II): Lyophilic colloid - Protective colloid
• (B)-(I): Emulsion - Liquid-liquid colloid
• (C)-(IV): Positively charged - \( \text{FeCl}_3 + \text{hot water} \)
• (D)-(III): Negatively charged - \( \text{FeCl}_3 + \text{NaOH} \)

Thus, the correct answer is: (A)-(II), (B)-(I), (C)-(IV), (D)-(III).