Question

Match List I with List II. 

Choose the correct answer from the options given below : 
 

• (a) $\to$ (iv), (b) $\to$ (iii), (c) $\to$ (i), (d) $\to$ (ii)
• (a) $\to$ (iii), (b) $\to$ (ii), (c) $\to$ (iv), (d) $\to$ (i)
• (a) $\to$ (iv), (b) $\to$ (i), (c) $\to$ (iii), (d) $\to$ (ii)
• (a) $\to$ (i), (b) $\to$ (ii), (c) $\to$ (iii), (d) $\to$ (iv)

Hint:

The vector that goes from the tail of the first to the head of the last is the sum. If you can walk around the whole triangle without ever meeting a head-to-head or tail-to-tail junction, the sum is zero.

Answer 1

The Correct Option is D

To solve the given problem, we need to match the vector equations from List I with their corresponding vector representations in List II.

Let's analyze each equation:

1. \vec{C} - \vec{A} - \vec{B} = 0

   This equation implies that the vector sum \vec{C} = \vec{A} + \vec{B}. This represents a vector triangle where \vec{C} is the resultant of \vec{A} and \vec{B}.

   Correspondence: Matches with Figure (i).

2. \vec{A} - \vec{C} - \vec{B} = 0

   In this case, \vec{A} = \vec{B} + \vec{C}. This indicates that \vec{A} is the resultant vector of \vec{B} and \vec{C}.

   Correspondence: Matches with Figure (ii).

3. \vec{B} - \vec{A} - \vec{C} = 0

   For this equation, \vec{B} = \vec{A} + \vec{C}. Thus, \vec{B} is the resultant of vectors \vec{A} and \vec{C}.

   Correspondence: Matches with Figure (iii).

4. \vec{A} + \vec{B} = -\vec{C}

   This equation denotes that \vec{C} is the vector opposite to the resultant of \vec{A} and \vec{B}.

   Correspondence: Matches with Figure (iv).

By matching each equation with its respective diagram, the correct answer is:

Option: (a) \to (i), (b) \to (ii), (c) \to (iii), (d) \to (iv)