Question

Match List-I with List-II and select the correct option.

• A. A-II, B-IV, C-I, D-III
• B. A-IV, B-I, C-II, D-III
• C. A-I, B-II, C-IV, D-III
• D. A-IV, B-II, C-I, D-III

Hint:

When determining the hybridization and magnetic moment, focus on the ligand geometry and the central metal's oxidation state. Use these to determine the appropriate geometry (tetrahedral, square planar, or octahedral) and calculate the number of unpaired electrons for the magnetic moment.

Answer 1

The Correct Option is D

Step 1: Analyze complexes and their coordination geometry
\([NiCl_4]^{2-}\) is a tetrahedral complex, typically with \(sp^3\) hybridization and a magnetic moment of 3.87 BM.

\([Ni(CN_4)]^{2-}\) is a square planar complex, usually with \(dsp^2\) hybridization and no unpaired electrons, resulting in a magnetic moment of 0 BM.

\([CoCl_4]^{2-}\) is an octahedral complex, typically with \(sp^3d^2\) hybridization and a magnetic moment of 2.82 BM.

\([Ni(H_2O)_6]^{2+}\) is a tetrahedral complex, exhibiting \(sp^3\) hybridization and a magnetic moment of 2.82 BM.

Step 2: Match complexes with characteristics
A.
\([NiCl_4]^{2-}\) matches with IV: \(sp^3\), tetrahedral, 3.87 BM.
B.
\([Ni(CN_4)]^{2-}\) matches with II: \(dsp^2\), square planar, 0 BM.
C.
\([CoCl_4]^{2-}\) matches with I: \(sp^3d^2\), octahedral, 2.82 BM.
D.
\([Ni(H_2O)_6]^{2+}\) matches with III: \(sp^3\), tetrahedral, 2.82 BM.