The magnetic moment of an iron bar is M. It is now bent in such a way that it forms an arc section of a circle subtending an angle of 60° at the centre. The magnetic moment of this arc section is

Question

A model for a quantized motion of an electron in a uniform magnetic field B states that the flux passing through the orbit of the electron is $ \phi = n h / e $ where $n$ is an integer, $h$ is Planck's constant and $e$ is the magnitude of electron's charge. According to the model, the magnetic moment of an electron in its lowest energy state will be ($m$ is the mass of the electron):

Answer 1

Initial condition: R₀ equals L.

The equation $\frac{R\pi}{3}$ is equal to L.

Solving for R yields R = $\frac{3L}{\pi}$.

The expression for M' is m(2R) sin 30°.

Substituting the value of R, M' equals m(2)$\frac{3L}{\pi}$ × $\frac{1}{2}$, which simplifies to $\frac{3}{\pi}$mL, and can also be represented as $\frac{3M}{\pi}$.

The magnetic moment of an iron bar is M. It is now bent in such a way that it forms an arc section of a circle subtending an angle of 60° at the centre. The magnetic moment of this arc section is

The Correct Option is A

Solution and Explanation

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