Question:medium

m–chlorobenzaldehyde on treatment with 50\(\%\) KOH solution yields

Updated On: Feb 4, 2026
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The Correct Option is B

Solution and Explanation

Solution: Treatment of m-chlorobenzaldehyde with 50% KOH solution initiates the Cannizzaro reaction, a process applicable to aldehydes lacking alpha hydrogens.

Cannizzaro Reaction: This reaction converts an aldehyde into a carboxylic acid and an alcohol when subjected to a strong base, such as KOH. The mechanism involves aldehyde disproportionation, yielding the corresponding carboxylate and alcohol.

Reaction Process: The reaction involving m-chlorobenzaldehyde is represented as:

2 m-chlorobenzaldehyde + 50% KOH → m-chlorobenzoate + m-chlorobenzyl alcohol.

Final Products: The reaction yields m-chlorobenzoate ion and m-chlorobenzyl alcohol.

Consequently, the products are chlorobenzoate and m-chlorobenzyl alcohol.

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