Question

The number of \(\pi\)-bonds present in benzoic acid is:

• A. 5.
• B. 4.
• C. 7.
• D. 3.

Hint:

To calculate \(\pi\)-bonds in a molecule, count the double and triple bonds, as each contains one and two \(\pi\)-bonds respectively.

Answer 1

The Correct Option is A

Step 1: Benzoic Acid Structure.
Benzoic acid (\(C_6H_5COOH\)) comprises: A benzene ring with three alternating \(\pi\)-bonds. A carboxylic acid (\(-COOH\)) substituent. The carboxylic acid group includes: One \(\pi\)-bond within the C=O linkage. Zero \(\pi\)-bonds within the O-H linkage. Step 2: \(\pi\)-Bond Count.
\[\text{Benzene ring: } 3 \pi\text{-bonds}.\]\[\text{Carboxylic acid group: } 1 \pi\text{-bond (C=O)}.\]\[\text{Total } \pi\text{-bonds: } 3 + 1 = 4.\]Step 3: Final Result.
Benzoic acid contains 4 \(\pi\)-bonds.\[\therefore \text{The correct answer is: (A)}.\]