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$ \lim_{x \to \infty} \left(\frac{x+5}{x+2}\right)^{x+3} $ equals

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$\lim_{x \to \infty} (\frac{x+a}{x+b})^{x+c} = e^{a-b}$. Here $5-2=3$.

Updated On: Apr 10, 2026

$e$
$e^2$
$e^3$
$e^5$

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The Correct Option is C

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\( \lim_{x \to \infty} \left(\frac{x+5}{x+2}\right)^{x+3} \) equals

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The Correct Option is C

Solution and Explanation

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