Step 1: {Continuity at \( x = 0 \)}
Evaluate the limit of \( f(x) \) as \( x \to 0 \): \[ \lim_{x \to 0} \frac{x^2 \log(\cos x)}{\log(1 + x)} = \lim_{x \to 0} x^2 \cdot \log(\cos x) = 0 \cdot \log(1) = 0 \] Consequently, \( f(x) \) exhibits continuity at \( x = 0 \).
Step 2: {Differentiability at \( x = 0 \)}
Ascertain differentiability at \( x = 0 \) by computing the derivative at this point: \[ f'(0) = \lim_{h \to 0} \frac{f(h) - f(0)}{h} = \lim_{h \to 0} \frac{h^2 \log(\cos h)}{h \log(1 + h)} = 0 \] Therefore, \( f(x) \) is differentiable at \( x = 0 \).
Evaluate the following limit: $ \lim_{n \to \infty} \prod_{r=3}^n \frac{r^3 - 8}{r^3 + 8} $.
If \( f(x) \) is defined as follows:
$$ f(x) = \begin{cases} 4, & \text{if } -\infty < x < -\sqrt{5}, \\ x^2 - 1, & \text{if } -\sqrt{5} \leq x \leq \sqrt{5}, \\ 4, & \text{if } \sqrt{5} \leq x < \infty. \end{cases} $$ If \( k \) is the number of points where \( f(x) \) is not differentiable, then \( k - 2 = \)