Given expression:
\[ |3 \, \text{adj}(2 \, \text{adj}(|A|A))| \]
Step-by-step simplification:
\[ |3 \, \text{adj}(2|A|^2 \, \text{adj}A)| \]
\[ |3 \cdot 2^2 \cdot |A|^4 \, \text{adj}(\text{adj}A)| \]
Using the property \(|\text{adj}A| = |A|^{n-1}\), we substitute and simplify:
\[ 3^3 \cdot 2^6 \cdot |A|^{12} \cdot |A|^2 = 3^{-13} \cdot 2^{-10} \]
This leads to:
\[ |A|^{16} = 3^{-16} \cdot 2^{-16} \]
Therefore,
\[ |A| = \frac{1}{6} \]
Substituting back into the main equation:
\[ |3 \, \text{adj}(2A)| = |3 \cdot 2^2 \, \text{adj}A| = 3^3 \cdot 2^6 |A|^2 \]
\[ = 3 \cdot 2^4 \]
Result:
\[ M = 4, \quad n = 1 \]
And,
\[ |3m + 2n| = 14 \]



