Let \(P=(0,2)\). Let \(A(x_1,y_1)\) and \(B(x_2,y_2)\) be two points on the circle \(x^2+y^2-6x+4y+4=0\) such that \(PA\) is minimum and \(PB\) is maximum. Then \(\frac{3(y_1-y_2){(x_2-x_1)}=\)}
Show Hint
Nearest and farthest points from an external point lie on the line joining point and center.