To solve the problem, we examine points on the curve y5 – 9xy + 2x = 0 where the tangents are either parallel to the x-axis or y-axis.
1. Tangents parallel to the x-axis:
The slope of the tangent is derived from the implicit differentiation of the curve:
Differentiating w.r.t. x, we obtain: 5y4 (dy/dx) – 9(y + x dy/dx) + 2 = 0.
Rearranging gives: (5y4 – 9x) dy/dx = 9y – 2.
For dy/dx = 0 (x-axis tangents), 9y – 2 = 0, so y = 2/9.
Substitute y = 2/9 into the original equation: (2/9)5 – 9x(2/9) + 2x = 0.
Simplifying, we find x = 2/13122.
Hence, there is 1 point, so M = 1.
2. Tangents parallel to the y-axis:
For vertical tangents, dy/dx is undefined. This occurs when 5y4 – 9x = 0, or x = (5/9)y4.
Substitute into the original equation:
y5 – 9(5/9)y4y + 2(5/9)y4 = 0.
Simplifies to (50/9)y4 = 0, yielding y = 0.
Substitute y = 0 into x = (5/9)y4, giving x = 0.
Thus, there is 1 point, so N = 1.
Therefore, M + N = 2.
This result falls within the provided range (2,2), validating our solution.