Question:medium
Let \(f(x) = x^p \cos(1/x)\) when \(x \neq 0\) and \(f(x) = 0\), when \(x = 0\). Then \(f(x)\) will be differentiable at \(x = 0\), if
Let \(f(x) = x^p \cos(1/x)\) when \(x \neq 0\) and \(f(x) = 0\), when \(x = 0\). Then \(f(x)\) will be differentiable at \(x = 0\), if
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For differentiable at 0, need \(p>1\); for continuous at 0, need \(p>0\).
Updated On: Apr 7, 2026
- \(p>0\)
- \(p>1\)
- \(0<p<1\)
- \(1/2<p<1\)
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The Correct Option is B
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