Step 1: Interpreting the given relation.
The condition stated in the problem is $A^2 = A$. This indicates that multiplying the matrix $A$ by itself yields the same matrix $A$.
Step 2: Relevant matrix definition.
A square matrix is said to be idempotent if it satisfies the relation \[ A^2 = A \] This definition exactly matches the condition provided in the question.
Step 3: Evaluation of the options.
(A) Nilpotent: A nilpotent matrix satisfies $A^k = 0$ for some positive integer $k$, which does not apply here.
(B) Idempotent: Correct, since an idempotent matrix is defined by $A^2 = A$.
(C) Involutory: An involutory matrix satisfies $A^2 = I$, where $I$ denotes the identity matrix, which is different from the given condition.
(D) Singular: A singular matrix has a determinant equal to zero; this property is not implied by the given relation.
Step 4: Final inference.
Because the matrix fulfills the condition $A^2 = A$, it is correctly identified as an idempotent matrix.
For the feasible region shown below, the non-trivial constraints of the linear programming problem are 
For the linear programming problem: \[ {Maximize} \quad Z = 2x_1 + 4x_2 + 4x_3 - 3x_4 \] subject to \[ \alpha x_1 + x_2 + x_3 = 4, \quad x_1 + \beta x_2 + x_4 = 8, \quad x_1, x_2, x_3, x_4 \geq 0, \] consider the following two statements:
S1: If \( \alpha = 2 \) and \( \beta = 1 \), then \( (x_1, x_2)^T \) forms an optimal basis.
S2: If \( \alpha = 1 \) and \( \beta = 4 \), then \( (x_3, x_2)^T \) forms an optimal basis. Then, which one of the following is correct?