Question:medium

There are two types of fertilizers $F_1$ and $F_2$. $F_1$ consists of 10% nitrogen and 6% phosphoric acid. $F_2$ consists of 5% nitrogen and 10% phosphoric acid.
After testing the soil conditions, a farmer finds that he needs at least 14 kg of nitrogen and 14 kg of phosphoric acid for his crop.
If $F_1$ costs ₹ 6 per kg and $F_2$ costs ₹ 5 per kg, how much of each type of fertilizer should be used so that the cost is minimum.
Formulate a linear programming problem.

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To formulate an LPP, define variables for quantities, translate constraints from the problem, and clearly state the objective function to minimize or maximize.
Updated On: Jan 14, 2026
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Solution and Explanation

Let $x$ represent the quantity (in kg) of fertilizer $F_1$ used.
Let $y$ represent the quantity (in kg) of fertilizer $F_2$ used.
Fertilizer $F_1$ contains 10% nitrogen, contributing $0.10x$ kg of nitrogen.
Fertilizer $F_2$ contains 5% nitrogen, contributing $0.05y$ kg of nitrogen.
The total nitrogen requirement must be at least 14 kg.
Thus, the nitrogen constraint is: $0.10x + 0.05y \geq 14$
Similarly, $F_1$ contains 6% phosphoric acid, contributing $0.06x$ kg.
$F_2$ contains 10% phosphoric acid, contributing $0.10y$ kg.
The total phosphoric acid requirement must be at least 14 kg.
Thus, the phosphoric acid constraint is: $0.06x + 0.10y \geq 14$
The cost of $F_1$ is ₹ 6 per kg, resulting in a cost of ₹ $6x$ for $x$ kg.
The cost of $F_2$ is ₹ 5 per kg, resulting in a cost of ₹ $5y$ for $y$ kg.
The objective is to minimize the total cost: $Z = 6x + 5y$
Additionally, quantities cannot be negative: $x \geq 0$, $y \geq 0$.
The linear programming problem is formulated as:
Minimize $Z = 6x + 5y$
Subject to the constraints:
$0.10x + 0.05y \geq 14$
$0.06x + 0.10y \geq 14$
$x \geq 0$, $y \geq 0$
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