Let $x$ represent the quantity (in kg) of fertilizer $F_1$ used.
Let $y$ represent the quantity (in kg) of fertilizer $F_2$ used.
Fertilizer $F_1$ contains 10% nitrogen, contributing $0.10x$ kg of nitrogen.
Fertilizer $F_2$ contains 5% nitrogen, contributing $0.05y$ kg of nitrogen.
The total nitrogen requirement must be at least 14 kg.
Thus, the nitrogen constraint is: $0.10x + 0.05y \geq 14$
Similarly, $F_1$ contains 6% phosphoric acid, contributing $0.06x$ kg.
$F_2$ contains 10% phosphoric acid, contributing $0.10y$ kg.
The total phosphoric acid requirement must be at least 14 kg.
Thus, the phosphoric acid constraint is: $0.06x + 0.10y \geq 14$
The cost of $F_1$ is ₹ 6 per kg, resulting in a cost of ₹ $6x$ for $x$ kg.
The cost of $F_2$ is ₹ 5 per kg, resulting in a cost of ₹ $5y$ for $y$ kg.
The objective is to minimize the total cost: $Z = 6x + 5y$
Additionally, quantities cannot be negative: $x \geq 0$, $y \geq 0$.
The linear programming problem is formulated as:
Minimize $Z = 6x + 5y$
Subject to the constraints:
$0.10x + 0.05y \geq 14$
$0.06x + 0.10y \geq 14$
$x \geq 0$, $y \geq 0$