Question:medium

The limit $\displaystyle \lim_{x \to 0} \frac{\sin x}{x}$ is equal to:

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This limit is the foundation of derivatives of trigonometric functions, especially $\frac{d}{dx}(\sin x) = \cos x$.
Updated On: Feb 9, 2026
  • $0$
  • $1$
  • $\infty$
  • Does not exist
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Interpreting the limit.  
The expression \[ \lim_{x \to 0} \frac{\sin x}{x} \] represents the value that the ratio $\frac{\sin x}{x}$ tends to as $x$ approaches zero from both the left and right sides. 

Step 2: Behavior near zero. 
As $x \to 0$, \[ \sin x \to 0 \quad \text{and} \quad x \to 0 \] Thus, the expression takes the indeterminate form $\frac{0}{0}$, indicating that direct substitution is not sufficient and the limit must be evaluated properly. 

Step 3: Applying a standard trigonometric limit. 
A well-known fundamental result in calculus is: \[ \lim_{x \to 0} \frac{\sin x}{x} = 1 \] This limit can be derived using geometric reasoning based on the unit circle or by comparing areas of triangles and circular sectors. 

Step 4: Intuitive understanding. 
When $x$ is very small (in radians), $\sin x$ is approximately equal to $x$. Therefore, the ratio $\frac{\sin x}{x}$ approaches $1$ as $x$ becomes closer to zero. 

Step 5: Checking the given options. 
(A) $0$: Incorrect, since $\sin x$ and $x$ approach zero at nearly the same rate. 
(B) $1$: Correct, because the ratio tends to $1$ as $x \to 0$. 
(C) $\infty$: Incorrect, the expression remains finite near zero. 
(D) Does not exist: Incorrect, as both left-hand and right-hand limits are equal. 

Step 6: Final result. 
Since $\frac{\sin x}{x}$ approaches the same value from both sides as $x \to 0$, the value of the limit is 1
 

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