Question:medium

A continuous function on a closed and bounded interval is always:

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Always associate “continuous + closed and bounded interval” with the Extreme Value Theorem.
Updated On: Feb 9, 2026
  • Differentiable
  • Monotonic
  • Bounded and attains its bounds
  • Periodic
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The Correct Option is C

Solution and Explanation

Step 1: Interpreting the given information. 
We are told that a function is continuous on an interval that is both closed and bounded. Such an interval can be written as \([a, b]\), where both endpoints are included and \(a < b\).

Step 2: Relevant mathematical result.
A key theorem applicable here is the Extreme Value Theorem. It states that if a function is continuous on a closed and bounded interval, then:

  • The function does not grow without limit (it is bounded).
  • The function actually reaches a highest value (maximum) and a lowest value (minimum) somewhere in the interval.

Step 3: Evaluating the statements.
(A) Differentiable: Not necessarily true. Continuity alone does not ensure differentiability.
(B) Monotonic: Not guaranteed. A continuous function may increase in some parts and decrease in others.
(C) Bounded and attains its bounds: This is exactly what the Extreme Value Theorem guarantees.
(D) Periodic: Continuity on a finite interval does not imply periodic behavior.

Step 4: Final conclusion.
Every continuous function defined on a closed and bounded interval is bounded and achieves both its maximum and minimum values.

\[ \boxed{\text{Bounded and attains its bounds}} \]

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