Question:medium

TLC
In the given TLC, the distance of spot \( A \) and \( B \) are 5 cm and 7 cm, from the bottom of the TLC plate, respectively. The \( R_f \) value of \( B \) is \( x \times 10^{-1} \) times more than \( A \). The value of \( x \) is _________ .

Updated On: Feb 2, 2026
Show Solution

Correct Answer: 15

Solution and Explanation

The retention factor (\( R_f \)) is defined as the ratio of the distance a compound travels to the distance the solvent front travels. The solvent front advanced 10 cm. \( R_f \) values for spots \( A \) and \( B \) are calculated as follows:

\( R_{fA} = \frac{5\, \text{cm}}{10\, \text{cm}} = 0.5 \)

\( R_{fB} = \frac{7\, \text{cm}}{10\, \text{cm}} = 0.7 \)

Given that \( R_{fB} \) is \( x \times 10^{-1} \) times greater than \( R_{fA} \):

\( 0.7 = x \times 10^{-1} \times 0.5 \)

Solving for \( x \):
\( 0.7 = \frac{x}{10} \times 0.5 \)
\( x = \frac{0.7 \times 10}{0.5} = 14 \)

The value of \( x \) is 14, which is within the specified range of 15,15.

Was this answer helpful?
1