In the given circuit the input voltage Vin is shown in figure. The cut-in voltage of p–n junction diode (D1 or D2) is 0.6 V. Which of the following output voltage (V0) waveform across the diode is correct?
To determine the output voltage waveform \( V_0 \) across the diodes \( D_1 \) and \( D_2 \), let's analyze the given circuit and input waveform.
The input voltage \( V_{\text{in}} \) varies sinusoidally between -10.6 V and +10.6 V. The diodes in the circuit have a cut-in voltage (forward voltage drop) of 0.6 V.
Positive Cycle:
During the positive half-cycle of \( V_{\text{in}} \), when \( V_{\text{in}} > 0.6 \, \text{V} \), diode \( D_1 \) becomes forward-biased and conducts.
When \( D_1 \) conducts, the output voltage \( V_0 \) approximately equals the forward voltage drop across \( D_1 \), which is 0.6 V.
Negative Cycle:
During the negative half-cycle of \( V_{\text{in}} \), when \( V_{\text{in}} < -0.6 \, \text{V} \), diode \( D_2 \) becomes forward-biased and conducts.
When \( D_2 \) conducts, the output voltage \( V_0 \) approximately equals the forward voltage drop across \( D_2 \), which is -0.6 V.
Based on the above analysis, the output voltage waveform \( V_0 \) toggles between +0.6 V and -0.6 V, following the diode's forward conduction behavior during each half-cycle of the input voltage.
The correct answer matches the option with the waveform where \( V_0 \) is clipped to \(\pm 0.6 \, \text{V}\).
