Question

Which of the following circuits would have the diode in conducting state?

• A.
• B.
• C.
• D.

Answer 1

The Correct Option is B

To determine which of the given circuits has the diode in a conducting state, we need to understand when a diode conducts. A diode conducts when it is forward-biased. This means the anode (positive side) is at a higher electrical potential than the cathode (negative side).

In a circuit, if the voltage applied across a diode makes its anode more positive than its cathode, the diode will be forward-biased and thus conduct current. Conversely, if the cathode is more positive, the diode will be reverse-biased and will not conduct.

Let's evaluate the given options to identify in which case the diode is forward-biased:

1. For the first circuit option:

   

   In this circuit, if we assume a typical orientation, check the voltage levels at the anode and cathode of the diode. If the anode is more positive than the cathode, the diode will conduct. Otherwise, it will not.

2. For the second circuit option:

   

   In this option, observe the voltage supply across the diode. If the anode is at a higher potential than the cathode, it indicates a forward bias, and the diode will conduct.

   This option is correctly designed to keep the diode forward-biased, hence the diode is in the conducting state.

3. For the third circuit option:

   

   Evaluate the potential across the diode. If it's reverse-biased, the diode will not conduct; otherwise, it will.

4. For the fourth circuit option:

   

   Similarly, check the potential difference. A backward orientation in the potential makes the diode non-conducting.

After evaluating all options, the second option shows the correct configuration where the diode is forward-biased and thus will be in the conducting state.

Conclusion: The correct option where the diode is in a conducting state is: