Cations are reduced at the cathode; anions are oxidized at the anode.
During the electrolysis of molten \( \mathrm{NaCl} \), an ionic compound comprising sodium ions (\( \mathrm{Na}^+ \)) and chloride ions (\( \mathrm{Cl}^- \)), the product at the cathode is identified.
Electrolysis requires melting the compound to liberate ions for electrode migration. The cathode, being negatively charged, attracts positively charged cations.
The electrode reactions in molten \( \mathrm{NaCl} \) electrolysis are:
As the cathode attracts \( \mathrm{Na}^+ \) ions, which are then reduced to sodium metal, the substance produced at the cathode in the electrolysis of molten \( \mathrm{NaCl} \) is sodium metal.
If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]