Question:medium

A sequence is defined as follows: \( a_1 = 1, a_2 = 2 \), and \( a_n = a_{n-1} + a_{n-2} \) for \( n \geq 3 \). What is the 6th term of the sequence?

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For recursive sequences, compute each term iteratively using the given relation and initial conditions. Double-check the term number.
Updated On: Nov 26, 2025
  • 5
  • 8
  • 13
  • 21
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The Correct Option is C

Solution and Explanation

Phase 1: Compute sequence terms iteratively. The recurrence relation is \( a_n = a_{n-1} + a_{n-2} \), with initial values \( a_1 = 1 \) and \( a_2 = 2 \).
Phase 2: Term calculation.
- \( a_3 = a_2 + a_1 = 2 + 1 = 3 \),
- \( a_4 = a_3 + a_2 = 3 + 2 = 5 \),
- \( a_5 = a_4 + a_3 = 5 + 3 = 8 \),
- \( a_6 = a_5 + a_4 = 8 + 5 = 13 \).
Phase 3: Pinpoint the 6th term. The 6th term is \( a_6 = 13 \).
Phase 4: Sequence validation.
The generated sequence is 1, 2, 3, 5, 8, 13, which aligns with the expected Fibonacci-like progression, thus validating the computation.
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