Question:medium

What is the percentage composition of nitrogen in ammonium nitrate (\( \text{NH}_4\text{NO}_3 \))?

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Remember: To find the percentage composition of an element in a compound, divide the total mass of that element by the molar mass of the compound and multiply by 100.
Updated On: Jan 13, 2026
  • 18.5%
  • 28.0%
  • 35.0%
  • 42.5%
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The Correct Option is A

Solution and Explanation

Step 1: Determine the molar mass of ammonium nitrate The chemical formula for ammonium nitrate is \( \text{NH}_4\text{NO}_3 \). The atomic masses of its constituent elements are: - Nitrogen (N) = 14 g/mol - Hydrogen (H) = 1 g/mol - Oxygen (O) = 16 g/mol The molar mass of \( \text{NH}_4\text{NO}_3 \) is calculated as follows: \[ M_{\text{NH}_4\text{NO}_3} = (1 \times 14) + (4 \times 1) + (1 \times 14) + (3 \times 16) = 14 + 4 + 14 + 48 = 80 \, \text{g/mol} \] Step 2: Calculate the mass contributed by nitrogen in ammonium nitrate Ammonium nitrate contains two nitrogen atoms. Therefore, the total mass of nitrogen is: \[ \text{Mass of nitrogen} = 2 \times 14 = 28 \, \text{g/mol} \] Step 3: Compute the percentage composition of nitrogen The percentage of nitrogen by mass in ammonium nitrate is derived using the following formula: \[ \text{Percentage of nitrogen} = \left( \frac{\text{Mass of nitrogen}}{\text{Molar mass of NH}_4\text{NO}_3} \right) \times 100 = \left( \frac{28}{80} \right) \times 100 = 35\% \] Answer: The percentage composition of nitrogen in ammonium nitrate is \( 35.0\% \). This corresponds to option (3).
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