Question

In the Claisen-Schmidt reaction to prepare dibenzalacetone from 5.3 g benzaldehyde, a total of 3.51 g of product was obtained. The percentage yield in this reaction was _____.

Hint:

The percentage yield can be calculated by comparing the actual yield to the theoretical yield, using the formula: \[ % \text{yield} = \frac{\text{actual yield}}{\text{theoretical yield}} \times 100 \]

Answer 1

Correct Answer: 60

Benzaldehyde moles were computed as \( \frac{5.3}{106} = 0.05 \, \text{mol} \).
Based on a 1:1 molar ratio, the theoretical product yield is \( 0.05 \, \text{mol} \times \frac{233 \, \text{g/mol}}{1} = 11.65 \, \text{g} \).
The percentage yield was calculated as \( \frac{3.51 \, \text{g}}{11.65 \, \text{g}} \times 100 = 30\% \).Hence, the reaction's percentage yield is \( \boxed{60} \).