To calculate the percentage of phosphorus in the given organic compound, we first need to analyze the reaction involved and then apply the stoichiometry of the compounds.
The compound given in the problem produces \(\mathrm{Mg_2P_2O_7}\)upon reaction. We are given:
First, we need to determine how much phosphorus is present in \(\mathrm{Mg_2P_2O_7}\). For this, we utilize the molar masses:
In \(\mathrm{Mg_2P_2O_7}\), there are two phosphorus atoms, so the mass of phosphorus in \(\mathrm{Mg_2P_2O_7}\)is:
| Formula: | \(2 \times 30.97 = 61.94\, \mathrm{g/mol}\) |
The mass fraction of phosphorus in \(\mathrm{Mg_2P_2O_7}\)is:
| Mass fraction: | \(\frac{61.94}{222.55}\) |
Calculating the mass of phosphorus in the \(0.93\, \mathrm{g}\) of \(\mathrm{Mg_2P_2O_7}\):
| Phosphorus mass: | \(0.93 \times \frac{61.94}{222.55} = 0.2586\, \mathrm{g}\) |
Now, calculate the percentage of phosphorus in the original compound:
| Percentage: | \(\frac{0.2586}{0.60} \times 100 = 43.1\%\) |
The percentage of phosphorus, rounded to the nearest integer, is 43%. However, this calculation reveals that the setup should verify the scenario where percentages, question options, and calculations are aligned. Let's identify that every methodological breakdown or application should question its context compliance. Kindly note identical practices for academic verification might ensure consistency.
The correct answer given in the question is 26, indicating that an additional perspective or type from the examiner might necessitate correction or question recourse.
Given below are two statements:
Statement I: In the oxalic acid vs KMnO$_4$ (in the presence of dil H$_2$SO$_4$) titration the solution needs to be heated initially to 60°C, but no heating is required in Ferrous ammonium sulphate (FAS) vs KMnO$_4$ titration (in the presence of dil H$_2$SO$_4$).
Statement II: In oxalic acid vs KMnO$_4$ titration, the initial formation of MnSO$_4$ takes place at high temperature, which then acts as catalyst for further reaction. In the case of FAS vs KMnO$_4$, heating oxidizes Fe$^{2+}$ into Fe$^{3+}$ by oxygen of air and error may be introduced in the experiment.
In the light of the above statements, choose the correct answer from the options given below: