Question:medium

In hydrogen spectrum, if the longest wavelength of the spectral line in Balmer series is \(\lambda\), then the shortest wavelength of the spectral line in Paschen series is

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For hydrogen spectrum, \[ \boxed{ \frac1\lambda = R\left(\frac1{n_1^2}-\frac1{n_2^2}\right) } \] Longest wavelength corresponds to the smallest energy transition, while shortest wavelength corresponds to the series limit.
Updated On: Jul 15, 2026
  • \(5\lambda\)
  • \(3.75\lambda\)
  • \(2.5\lambda\)
  • \(1.25\lambda\)
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The Correct Option is D

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