Question

In an open tube manometer, the volume of the gas enclosed in the bulb is \(250\,\mathrm{cm^3}\) and the difference in the heights of the liquid levels in the manometer is \(125\,\mathrm{cm}\). The density of the liquid in the manometer is \[ \left( g=10\,\mathrm{m\,s^{-2}},\; P_{\text{atm}}=100\,\mathrm{kPa} \right) \]

• A. \(12.5\,\mathrm{kg\,m^{-3}}\)
• B. \(0.16\,\mathrm{kg\,m^{-3}}\)
• C. \(4.8\,\mathrm{kg\,m^{-3}}\)
• D. \(8\times10^{3}\,\mathrm{kg\,m^{-3}}\)

Hint:

For an open tube manometer, \[ \boxed{ \Delta P=\rho gh } \] where \(h\) is the difference in the liquid levels.

Answer 1

The Correct Option is D