Question

In a vernier calipers 50 VSD are equal to 48 MSD. 1 MSD is equal to $0.05$ mm. Find least count of this vernier calipers.

• A. $0.005$ mm
• B. $0.004$ mm
• C. $0.001$ mm
• D. $0.002$ mm

Hint:

Least count equals difference between one main scale division and one vernier scale division.

Answer 1

The Correct Option is D

Step 1: Understand the given data

50 Vernier Scale Divisions (VSD) = 48 Main Scale Divisions (MSD)

1 MSD = 0.05 mm

---

Step 2: Find the value of 1 Vernier Scale Division

1 VSD = (48 / 50) MSD

1 VSD = 0.96 MSD

Converting into millimetres:

1 VSD = 0.96 × 0.05 mm = 0.048 mm

---

Step 3: Calculate the least count

Least Count = 1 MSD − 1 VSD

Least Count = 0.05 mm − 0.048 mm

Least Count = 0.002 mm

---

Final Answer:

The least count of the vernier calipers is
0.002 mm