Question:medium

In a photoelectric experiment, if the intensity of incident light is doubled and the frequency is kept slightly greater than threshold frequency, then the saturation photoelectric current

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Intensity affects current, frequency affects energy of electrons.
Updated On: May 14, 2026
  • remains constant
  • is halved
  • is doubled
  • becomes four times
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The saturation photoelectric current corresponds to the state where all electrons ejected per second are collected by the anode.
The number of electrons ejected per second is directly proportional to the number of photons incident per second, which is defined as the intensity of light.
Step 2: Key Formula or Approach:
Photoelectric current \(I \propto\) Intensity of incident radiation.
Saturation current isreached when all photoelectrons are contributing to the circuit current.
Step 3: Detailed Explanation:
The frequency of incident light is given to be greater than the threshold frequency, ensuring that photoemission occurs.
Intensity of light is defined as energy per unit area per unit time. For monochromatic light, doubling the intensity means doubling the number of photons hitting the surface per unit time.
Since one photon (ideally) interacts with one electron, doubling the number of incident photons will double the number of ejected electrons.
Consequently, the saturation current (the maximum current possible for a given intensity) will also double.
Step 4: Final Answer:
The saturation photoelectric current is doubled.
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