Question

If \(y^{1/m} + y^{-1/m} = 2x\), then \((x^2 - 1)y'' + xy'\) is equal to

• A. \(m^2 y\)
• B. \(-m^2 y\)
• C. \(\pm m^2 y\)
• D. None of these

Hint:

The expression \(x \pm \sqrt{x^2 - 1}\) appears in the solution of \((x^2 - 1)y'' + xy' = m^2 y\).

Answer 1

The Correct Option is A