Question:medium
If
\[
\sum_{k=1}^{n} a_k = 6n^3,
\]
then}
\[
\sum_{k=1}^{6}\left(\frac{a_{k+1}-a_k}{36}\right)^2
\]
is equal to _______.
If
\[
\sum_{k=1}^{n} a_k = 6n^3,
\]
then}
\[
\sum_{k=1}^{6}\left(\frac{a_{k+1}-a_k}{36}\right)^2
\]
is equal to _______.
Updated On: Apr 10, 2026
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Correct Answer: 91
Solution and Explanation
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