Question:medium
If \( S_1: x^2 + y^2 - 6x - 8y + 21 = 0 \) and \( S_2: x^2 + y^2 + 6x + 8y + \lambda = 0 \), then the distance of the centre of \( S_2 \) to the farthest point on \( S_1 \) is:
If \( S_1: x^2 + y^2 - 6x - 8y + 21 = 0 \) and \( S_2: x^2 + y^2 + 6x + 8y + \lambda = 0 \), then the distance of the centre of \( S_2 \) to the farthest point on \( S_1 \) is:
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For any point \( P \) and circle with centre \( C \) and radius \( r \), the nearest distance is \( |PC - r| \) and the farthest distance is \( PC + r \).
Updated On: Apr 6, 2026
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The Correct Option is C
Solution and Explanation
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