The provided logarithmic equation is:
\[ 5 - \log_{10} \left( \sqrt{1+x} + 4 \log_{10} \sqrt{1-x} \right) = \log_{10} \frac{1}{\sqrt{1-x^2}} \]
This equation is simplified through a series of steps.
The initial equation is rewritten as:
\[ 5 - \log_{10} \left( \sqrt{1+x} + 4 \log_{10} \sqrt{1-x} \right) = \log_{10} \left( \frac{1}{\sqrt{1-x^2}} \cdot \frac{1}{\sqrt{1-x}} \right) \]
Further simplification involves factoring and solving.
The left-hand side of the equation is simplified using logarithmic properties:
\[ 5 \log_{10} \left( \sqrt{1+x} + 4 \log_{10} \sqrt{1-x} \right) = \log_{10} \sqrt{1-x} = -\log_{10} \sqrt{1-x} \cdot \log_{10} \sqrt{1+x} \]
Logarithmic rules are applied to combine terms:
\[ 4 \log_{10} \left( \sqrt{1-x} \right) + \log_{10} \left( \sqrt{1-x} \right) = -5 \]
This simplifies to:
\[ \log_{10} \left( \sqrt{1-x} \right) = -1 \]
The equation is solved for \( x \):
\[ \sqrt{1-x} = \frac{1}{10} \]
Squaring both sides eliminates the square root:
\[ 1 - x = \frac{1}{100} \]
Solving for \( x \) yields:
\[ x = 1 - \frac{1}{100} = \frac{99}{100} \]
The value of \( x \) is \( \frac{99}{100} \), and the solution is 99/100.
If \[ \log_{p^{1/2}} y \times \log_{y^{1/2}} p = 16, \] then find the value of the given expression.