Question

Identify the product formed (A and E)

• A.
• B.
• C.
• D.

Answer 1

The Correct Option is C

To identify the products formed in the reaction sequence, we need to follow each step and understand the transformations occurring at each stage:

1. The starting compound is p-nitrotoluene with a bromine atom attached to the benzene ring. Initially, the reaction with \(Br_2\) will lead to bromination at the meta position relative to the methyl group. Thus, product A is meta-bromo-p-nitrotoluene.
2. Treatment with \(Sn/HCl\) is a reduction step indicating the conversion of the nitro group (\(NO_2\)) to an amino group (\(NH_2\)), forming product B — p-amino-m-bromo-toluene.
3. The next step involves diazotization with \(NaNO_2/HCl\) at 273-278 K, converting the amino group into a diazonium salt. This leads to product C — the diazonium compound.
4. On heating with \(H_3PO_2\), the diazonium salt undergoes reduction, which typically results in the removal of the diazo group, leading to product D — m-bromo-toluene.
5. Finally, the oxidation step using \(KMnO_4/KOH\) converts the methyl group into a carboxyl group, producing product E — m-bromo-benzoic acid.

Considering the sequence of reactions and the transformations, product E is a m-bromo-benzoic acid.

Thus, the correct answer involves understanding how each reagent affects the moieties on the benzene ring, leading to the deduction of the final product structure.

The identified correct product image from the options is:

Correct answer is (c)