Question:medium

How many moles of urea is present in \(250\) ml of \(0.2\,M\) solution of it?

Show Hint

For molarity questions, always convert volume from ml to litre before applying \(n=MV\).
  • \(0.03\)
  • \(0.04\)
  • \(0.05\)
  • \(0.06\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
This is a straightforward calculation based on the definition of molarity. Molarity (M) is a unit of concentration, defined as the number of moles of solute per liter of solution.
Step 2: Key Formula or Approach:
The formula for molarity is: \[ \text{Molarity (M)} = \frac{\text{moles of solute (n)}}{\text{Volume of solution in liters (V)}} \] We can rearrange this formula to solve for the number of moles: \[ n = M \times V \] Step 3: Detailed Explanation:
Given: - Molarity of the urea solution, M = 0.2 mol/L. - Volume of the solution = 250 ml. First, we must convert the volume from milliliters (ml) to liters (L): \[ V = 250 \text{ ml} \times \frac{1 \text{ L}}{1000 \text{ ml}} = 0.250 \text{ L} \] Now, use the rearranged formula to calculate the number of moles (n): \[ n = M \times V \] \[ n = 0.2 \frac{\text{mol}}{\text{L}} \times 0.250 \text{ L} \] \[ n = 0.05 \text{ mol} \] Step 4: Final Answer:
There are 0.05 moles of urea present in the solution. Therefore, option (C) is correct.
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