To solve this problem, let's first understand the concepts of Williamson synthesis and analyze the given statements.
Assertion (A): Synthesis of ethyl phenyl ether may be achieved by Williamson synthesis.
The Williamson synthesis is a reaction used to produce ethers. It involves the reaction of an alkoxide ion with a primary alkyl halide via an SN2 mechanism. Thus, it is possible to synthesize ethyl phenyl ether (C6H5OC2H5) using ethoxide ions and an appropriate halide. Given the reaction is an SN2 type, it works efficiently with primary alkyl halides.
Reason (R): Reaction of bromobenzene with sodium ethoxide yields ethyl phenyl ether.
The reaction between bromobenzene (C6H5Br) and sodium ethoxide (C2H5ONa) does not proceed via an SN2 mechanism because the carbon atom in bromobenzene is sp2 hybridized, which makes nucleophilic aromatic substitution difficult. Bromobenzene is not suitable for Williamson synthesis because the phenyl group does not undergo the SN2 reaction. Therefore, ethyl phenyl ether cannot be formed by this method.
Now, let's evaluate the options:
Hence, the correct answer is: (A) is correct but (R) is not correct.
Calculate the potential for half-cell containing 0.01 M K\(_2\)Cr\(_2\)O\(_7\)(aq), 0.01 M Cr\(^{3+}\)(aq), and 1.0 x 10\(^{-4}\) M H\(^+\)(aq).
