A, B, C, D & E
B & C only
B, C & D only
A, C & D only
Let's analyze each statement about the molecules and ions given in the question to determine which of them are correct:
Explanation: Ammonia \((\mathrm{NH_3})\) has a higher dipole moment than nitrogen trifluoride \((\mathrm{NF_3})\). This is due to the orientation of their bond dipoles. In \(\mathrm{NH_3}\), the lone pair of electrons is directed upwards, enhancing the dipole, while in \(\mathrm{NF_3}\), the lone pair is directed against the bond dipoles of the N-F bonds, which reduces the net dipole moment. Hence, this statement is incorrect.
Explanation: Beryllium hydride \((\mathrm{BeH_2})\) is linear, and the dipole moments of the two Be-H bonds cancel each other out. Therefore, the molecule has a net dipole moment of zero. This statement is correct.
Explanation: The bond order of \(\mathrm{O_2^{2-}}\) (peroxide ion) is 1, and the bond order of \(\mathrm{F_2}\) is also 1. Therefore, these two molecules have the same bond order. This statement is correct.
Explanation: In the ozone molecule \((\mathrm{O_3})\), the formal charge calculation shows that the central oxygen atom has a charge of -1. This statement is correct.
Explanation: The nitrogen dioxide molecule \((\mathrm{NO_2})\) has an odd number of valence electrons (17), so it does not satisfy the octet rule for all atoms. It is actually a free radical, which makes it reactive, not 'very stable'. Hence, this statement is incorrect.
Based on the analysis above, the correct statements are B, C, and D.
Correct Answer: B, C & D only
Consider the following compounds. Arrange these compounds in a n increasing order of reactivity with nitrating mixture. The correct order is : 