To understand how a transistor operates as a switch, we need to examine its behavior in different regions of operation. A transistor, specifically a Bipolar Junction Transistor (BJT), has three primary modes of operation: active, saturation, and cut-off.
Conclusion: For a transistor to function as a switch, it needs to alternately move between the saturation and cut-off states. In the saturation state, the transistor is "on," allowing current to pass through, representing a closed circuit state. Conversely, in the cut-off state, the transistor is "off," preventing current flow, simulating an open circuit. Therefore, the correct answer is the Saturation and cut-off state.
In the circuit shown, the identical transistors Q1 and Q2 are biased in the active region with \( \beta = 120 \). The Zener diode is in the breakdown region with \( V_Z = 5 \, V \) and \( I_Z = 25 \, mA \). If \( I_L = 12 \, mA \) and \( V_{EB1} = V_{EB2} = 0.7 \, V \), then the values of \( R_1 \) and \( R_2 \) (in \( k\Omega \), rounded off to one decimal place) are _________, respectively.

Given below are two statements :
Statement I : In a typical transistor, all three regions emitter, base and collector have same doping level.
Statement II : In a transistor, collector is the thickest and base is the thinnest segment.
In the light of the above statements, choose the most appropriate answer from the options given below.