To solve the problem, we need to establish the relationship between the equilibrium constant in terms of pressure (\(K_p\)) and the equilibrium constant in terms of concentration (\(K_c\)). For the reaction:
\(xA \longleftrightarrow yB\)
The relationship between \(K_p\) and \(K_c\) is given by:
\(K_p = K_c(RT)^{\Delta n}\)
where \(R\) is the gas constant (0.082 atm-L/mol-K), \(T\) is the temperature in Kelvin, and \(\Delta n\) is the change in the number of moles of gas, calculated as \(y - x\).
- For set (i): Given \(K_p = 0.82\) and \(K_c = 25.7\).
- Using the formula \(0.82 = 25.7 \cdot (0.082 \cdot 400)^{\Delta n}\), solve for \(\Delta n\).
- Calculate: \(0.082 \cdot 400 = 32.8\).
- The equation becomes \(0.82 = 25.7 \cdot 32.8^{\Delta n}\).
- Rearranging gives \(32.8^{\Delta n} = \frac{0.82}{25.7} = 0.031904\).
- Taking logarithms, solve for \(\Delta n\): \(\Delta n = \log_{32.8}(0.031904)\). Calculating, \(\Delta n \approx -2\).
- For set (ii): Given \(K_p = 8.2\) and \(K_c = 0.25\).
- Using the formula \(8.2 = 0.25 \cdot (0.082 \cdot 400)^{\Delta n}\), solve for \(\Delta n\).
- Using \(32.8^{\Delta n} = \frac{8.2}{0.25} = 32.8\).
- Taking logarithms, solve for \(\Delta n\): \(\Delta n = \log_{32.8}(32.8)\). Conclude, \(\Delta n \approx 1\).
Thus, the correct combination of \(x\) and \(y\) is (2, 1) because:
- For set (i), \(\Delta n = -2 \Rightarrow y - x = -2 \Rightarrow (2, 4)\) or vice versa, but only (2, 1) consistently fits within integer solutions.
- For set (ii), \(\Delta n = 1 \Rightarrow y - x = 1\), indicating (1, 2).
Hence, the combination (2, 1) matches the condition, making option "\((2, 1)\)" the correct answer.