To solve the problem, we need to establish the relationship between the equilibrium constant in terms of pressure (\(K_p\)) and the equilibrium constant in terms of concentration (\(K_c\)). For the reaction:
\(xA \longleftrightarrow yB\)
The relationship between \(K_p\) and \(K_c\) is given by:
\(K_p = K_c(RT)^{\Delta n}\)
where \(R\) is the gas constant (0.082 atm-L/mol-K), \(T\) is the temperature in Kelvin, and \(\Delta n\) is the change in the number of moles of gas, calculated as \(y - x\).
Thus, the correct combination of \(x\) and \(y\) is (2, 1) because:
Hence, the combination (2, 1) matches the condition, making option "\((2, 1)\)" the correct answer.
At a given temperature and pressure, the equilibrium constant values for the equilibria are given below:
$ 3A_2 + B_2 \rightleftharpoons 2A_3B, \, K_1 $
$ A_3B \rightleftharpoons \frac{3}{2}A_2 + \frac{1}{2}B_2, \, K_2 $
The relation between $ K_1 $ and $ K_2 $ is: