Question:medium

First diffraction minima due to a single slit of width \(10^{-4}\) cm is at \(\theta = 30^\circ\). Then wavelength of the light used is

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Single slit minima: \(a\sin\theta = n\lambda\) (n = 1, 2, ...). First minimum: \(n=1\). Remember \(1\ \AA = 10^{-10}\) m.
Updated On: Apr 8, 2026
  • 4000 \AA
  • 5000 \AA
  • 6000 \AA
  • 6250 \AA
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The Correct Option is B

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