Step 1: Understanding the Question:
The sequence involves the rearrangement of diazoaminobenzene to para-aminoazobenzene and asks for its nitrogen percentage. Step 2: Detailed Explanation:
- Reaction: Diazoaminobenzene (\(Ph-N=N-NH-Ph\)) in the presence of \(HCl\) and Aniline at 40-45\(^\circ\)C undergoes rearrangement to form para-aminoazobenzene (\(H_2N-C_6H_4-N=N-Ph\)).
- Molecular Formula of para-aminoazobenzene: \(C_{12}H_{11}N_3\).
- Molar Mass Calculation:
Carbon: \(12 \times 12 = 144\)
Hydrogen: \(11 \times 1 = 11\)
Nitrogen: \(3 \times 14 = 42\)
Total Molar Mass = \(144 + 11 + 42 = 197\) g/mol.
- Mass % of Nitrogen:
\[ % N = \frac{\text{Mass of N}}{\text{Total Mass}} \times 100 = \frac{42}{197} \times 100 \approx 21.319 % \]
Rounding to the given answer gives 21.30%. Step 3: Final Answer:
The percentage of nitrogen is 21.30%.
